y^{''}+k^2y^'=0

Lösung

y^{^{''}} + k^{2} y^{^{'}} = 0

y = c_{1} + c_{2} e^{- k^{2} t}

Schritte zur Lösung

y^{''} (t) + k^{2} y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- k^{2} t}

y = c_{1} + c_{2} e^{- k^{2} t}

(d^{2} + 1)^{2} y = 0

y^{^{''}} - 2 y^{^{'}} + y = 0, y (0) = 3 x^{4}

y^{^{'''}} - 7 y^{^{''}} + 6 y = 0

2 y^{^{''}} - y^{^{'}} = 0

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (0) = 2, y^{^{'}} (0) = - 3