y^{''}+ay=0,y(-1)=0,y(1)=0

Lösung

y^{^{''}} + a y = 0, y (- 1) = 0, y (1) = 0

y = 0

Schritte zur Lösung

y^{''} (t) + a y = 0

Solve linear ODE:

y = 0

y = 0

y^{^{''}} - y^{^{'}} - 30 y = 0, y (0) = x, y^{^{'}} (0) = 5

x^{^{''}} = a x

- 3 y^{^{''}} + \frac{1}{12} y = 0

\frac{1}{8} y^{^{''}} + 4 y^{^{'}} + 28 y = 0, y (0) = 0, y^{^{'}} (0) = 8

\frac{d ^{4} y}{d x ^{4}} - 2 \frac{d ^{2} y}{d x ^{2}} - 8 y = 0