What is the solution for derivative of f(x)=arcsec(x) ?

The solution for derivative of f(x)=arcsec(x) is f(x)=xarcsec(x)-ln(x+sqrt(x^2-1))+c_{1}

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Find the Derivative - d/dx f(x)=arcsec(x)

\frac{d}{d x} f (x) = arcsec (x)

f (x) = x arcsec (x) - ln (x + x^{2} - 1) + c_{1}

Solution steps

\frac{df}{d x} = arcsec (x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int arcsec (x) d x

\int arcsec (x) d x = x arcsec (x) - ln (x + x^{2} - 1) + c_{1}

f (x) = x arcsec (x) - ln (x + x^{2} - 1) + c_{1}

\frac{d}{d x} (\frac{x}{4})

\frac{d}{d x} (\frac{100}{x})

\frac{d}{d x} (2 x y)

f (x) = x^{2} + 2 x, 0 < x < 6

\frac{d}{d x} (tan (3 x))

What is the solution for derivative of f(x)=arcsec(x) ?
The solution for derivative of f(x)=arcsec(x) is f(x)=xarcsec(x)-ln(x+sqrt(x^2-1))+c_{1}