What is the integral of f(x)=x^{-2} ?

The integral of f(x)=x^{-2} is -1/x+C

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Find the Antiderivative f(x)=x^-2

integral

f (x) = x^{- 2}

- \frac{1}{x} + C

Solution steps

\int x^{- 2} d x

Apply the Power Rule

= - \frac{1}{x}

Add a constant to the solution

= - \frac{1}{x} + C

\frac{d}{d x} (5)

\frac{d}{d x} (2^{x})

\frac{d}{d x} (2 sec^{2} (x) tan (x))

\frac{d}{d x} (\frac{6}{x})

\frac{d}{d x} (\frac{1}{( x ^{2} )})