What is area y=e^{-x},y=0,x=0,x=ln(5) ?

The answer to area y=e^{-x},y=0,x=0,x=ln(5) is 4/5

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area y=e^{-x},y=0,x=0,x=ln(5)

area

y = e^{- x}, y = 0, x = 0, x = ln (5)

\frac{4}{5}

Decimal Notation

0.8

Solution steps

Apply the area formula:

\int_{0}^{l n (5)} e^{- x} d x

Solve

\int_{0}^{l n (5)} e^{- x} d x : \frac{4}{5}

The area is:

= \frac{4}{5}

x \to 3 lim (a x + 3)

y d x + (x^{2} - 4 x) d y = 0

n = 1 \sum \infty \frac{9 n}{n !}

(ln^{2} (x))^{^{'}}

x \to 2 lim (x^{3} - 3 x^{2} + 4)

What is area y=e^{-x},y=0,x=0,x=ln(5) ?
The answer to area y=e^{-x},y=0,x=0,x=ln(5) is 4/5