What is area y=x^2+2,y=-x,x=0,x=1 ?

The answer to area y=x^2+2,y=-x,x=0,x=1 is 17/6

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area y=x^2+2,y=-x,x=0,x=1

area

y = x^{2} + 2, y = - x, x = 0, x = 1

\frac{17}{6}

Decimal Notation

2.83333 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{2} + 2 + x d x

Solve

\int_{0}^{1} x^{2} + 2 + x d x : \frac{17}{6}

The area is:

= \frac{17}{6}

\int \frac{29}{( x + 1 ) ( x ^{2} + x )} d x

y = \frac{e ^{x}}{9 x ^{2}}

\int \frac{( x ^{2} )}{13 - 4 x + x ^{2}} d x

\frac{d}{d x} (\frac{x + 6}{x ^{3} + x - 1})

y^{^{''}} + 4 y^{^{'}} + 3 y = t e^{- t}

What is area y=x^2+2,y=-x,x=0,x=1 ?
The answer to area y=x^2+2,y=-x,x=0,x=1 is 17/6