What is the solution for (dy}{dx}-(\frac{1+x)/x)y=(y^2)/x ?

The solution for (dy}{dx}-(\frac{1+x)/x)y=(y^2)/x is y=(xe^x)/(-e^x+c_{1)}

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(dy}{dx}-(\frac{1+x)/x)y=(y^2)/x

\frac{d y}{d x} - (\frac{1 + x}{x}) y = \frac{y ^{2}}{x}

y = \frac{x e ^{x}}{- e ^{x} + c _{1}}

Solution steps

\frac{d y}{d x} - (\frac{1 + x}{x}) y = \frac{y ^{2}}{x}

Solve Bernoulli ODE:

y = \frac{x e ^{x}}{- e ^{x} + c _{1}}

y = \frac{x e ^{x}}{- e ^{x} + c _{1}}

\int_{1}^{3} 4 d x

f (x) = sin (2 x^{3})

\int_{1}^{2} x x^{2} - 1 d x

x \to \infty lim (x - 3 x^{4})

11 x - \frac{8}{x}

What is the solution for (dy}{dx}-(\frac{1+x)/x)y=(y^2)/x ?
The solution for (dy}{dx}-(\frac{1+x)/x)y=(y^2)/x is y=(xe^x)/(-e^x+c_{1)}