derivative 100-(200)/(sqrt(t^2+4))

Lösung

ableitung von

100 - \frac{200}{t ^{2} + 4}

\frac{200 t}{( t ^{2} + 4 ) ^{\frac{3}{2}}}

Schritte zur Lösung

\frac{d}{d t} (100 - \frac{200}{t ^{2} + 4})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (100) - \frac{d}{d t} (\frac{200}{t ^{2} + 4})

\frac{d}{d t} (100) = 0

\frac{d}{d t} (\frac{200}{t ^{2} + 4}) = - \frac{200 t}{( t ^{2} + 4 ) ^{\frac{3}{2}}}

= 0 - (- \frac{200 t}{( t ^{2} + 4 ) ^{\frac{3}{2}}})

Vereinfache

= \frac{200 t}{( t ^{2} + 4 ) ^{\frac{3}{2}}}

d er i v a t i v e - \frac{5}{x ^{5}}

y^{^{''}} + 25 y = cos (4 t)

n = 1 \sum \infty \frac{( n )}{2 ^{n}}

t an g e n t (x + 2)^{2} + (y - 3)^{2} = 37, (- 1, - 3)

\frac{d}{d x} (\frac{x ^{2} - 2}{x ^{3} + 3 x ^{2}})