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Beliebt Rechnen >

y^{''}+2y^'+10y=cos(t)+0.739

Lösung

y^{^{''}} + 2 y^{^{'}} + 10 y = cos (t) + 0.739

Lösung

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + 0.0739 + \frac{2 sin ( t ) + 9 cos ( t )}{85}

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 10 y = cos (t) + 0.739

Solve linear ODE:

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + 0.0739 + \frac{2 sin ( t ) + 9 cos ( t )}{85}

y = e^{- t} (c_{1} cos (3 t) + c_{2} sin (3 t)) + 0.0739 + \frac{2 sin ( t ) + 9 cos ( t )}{85}

Graph

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