What is the inverse of f(x)=x^2+3x-4 ?

The inverse of f(x)=x^2+3x-4 is (-3+sqrt(4x+25))/2 ,(-3-sqrt(4x+25))/2

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inverse of f(x)=x^2+3x-4

inverse

f (x) = x^{2} + 3 x - 4

\frac{- 3 + 4 x + 25}{2}, \frac{- 3 - 4 x + 25}{2}

Solution steps

y = x^{2} + 3 x - 4

Replace

x

with

y

x = y^{2} + 3 y - 4

Solve for

y, x = y^{2} + 3 y - 4

\frac{- 3 + 4 x + 25}{2}, \frac{- 3 - 4 x + 25}{2}

x + 2 y = 6, (1, - 3)

f (x) = \frac{x ^{2} - 9}{x ^{2} + 6}

3 \cdot 2^{x - 4} - 5

f (x) = \frac{( 1 - x )}{2 x - 1}

x^{2} - 6 x - 1

What is the inverse of f(x)=x^2+3x-4 ?
The inverse of f(x)=x^2+3x-4 is (-3+sqrt(4x+25))/2 ,(-3-sqrt(4x+25))/2