What is the range of f(x)=sqrt(4x-7) ?

The range of f(x)=sqrt(4x-7) is f(x)>= 0

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range of f(x)=sqrt(4x-7)

range

f (x) = 4 x - 7

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = \frac{2 x ^{2}}{x ^{2} - 1}

x^{3} - 48 x + 7

8 - x + 7

y = \frac{2}{∣ x ∣ - 2}

f (x) = (\frac{4}{3})^{x - 2}