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Popular >

f(x)=x^2-5x+4

Solution

f (x) = x^{2} - 5 x + 4

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - \frac{9}{4}

X Intercepts : (4, 0), (1, 0), Y Intercepts : (0, 4)

Vertex : Minimum (\frac{5}{2}, - \frac{9}{4})

Inverse : \frac{5 + 4 x + 9}{2}, \frac{5 - 4 x + 9}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{9}{4}, \infty)

Solution steps

Domain of

x^{2} - 5 x + 4 : - \infty < x < \infty

Range of

x^{2} - 5 x + 4 : f (x) \geq - \frac{9}{4}

Axis interception points of

x^{2} - 5 x + 4 :

X Intercepts

: (4, 0), (1, 0),

Y Intercepts

: (0, 4)

Vertex of

x^{2} - 5 x + 4 :

Minimum

(\frac{5}{2}, - \frac{9}{4})

Inverse of

x^{2} - 5 x + 4 : \frac{5 + 4 x + 9}{2}, \frac{5 - 4 x + 9}{2}

Popular Examples

inflection (x^3)/(x+1)inflection points

\frac{x ^{3}}{x + 1}

midpoint (-7,2),(3,-3)midpoint

(- 7, 2), (3, - 3)

critical f(x)=(x^2)/(x^2-4)critical points

f (x) = \frac{x ^{2}}{x ^{2} - 4}

range of f(x)=2x^2-7x-4 range

f (x) = 2 x^{2} - 7 x - 4

critical f(x)=-x^3+2x^2+2 critical points

f (x) = - x^{3} + 2 x^{2} + 2

Frequently Asked Questions (FAQ)

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