What is the inflection f(x)=x^3-2x^2-4x+2 ?

The inflection f(x)=x^3-2x^2-4x+2 is (2/3 ,-34/27)

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inflection f(x)=x^3-2x^2-4x+2

inflection points

f (x) = x^{3} - 2 x^{2} - 4 x + 2

(\frac{2}{3}, - \frac{34}{27})

Solution steps

f^{''} (x) = 6 x - 4

Find intervals:

Concave Downward

: - \infty < x < \frac{2}{3},

Concave Upward

: \frac{2}{3} < x < \infty

Plug

x = \frac{2}{3}

into

x^{3} - 2 x^{2} - 4 x + 2 : - \frac{34}{27}

(\frac{2}{3}, - \frac{34}{27})

f (x) = x^{3} - 27 x + 57

(6, - 2), (- 2, 3)

f (x) = \frac{x}{12}

f (x) = - \frac{3}{4} x^{4} - x^{3} + 3 x^{2}

f (x) = ln (ln (ln (4 x)))

What is the inflection f(x)=x^3-2x^2-4x+2 ?
The inflection f(x)=x^3-2x^2-4x+2 is (2/3 ,-34/27)