What is the domain of f(x)=2sqrt(x)+7 ?

The domain of f(x)=2sqrt(x)+7 is x>= 0

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domain of f(x)=2sqrt(x)+7

domain

f (x) = 2 x + 7

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = (x - 3)^{2} - 7

f (x) = \frac{1}{x ^{2} - 5 x + 6}

y = - 2 x + 2

f (x) = \frac{3 x ^{2} + 5 x - 7}{x ^{2} - 3}

f (x) = \frac{x ^{2} - 4 x + 3}{x ^{2} - 1}