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Popular >

midpoint (2,-6),(4,10)

Solution

midpoint

(2, - 6), (4, 10)

Solution

(3, 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 6), (x_{2}, y_{2}) = (4, 10)

= (\frac{4 + 2}{2}, \frac{10 - 6}{2})

Refine

= (3, 2)

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\frac{4}{\frac{x}{x + 4}}

domain of f(x)=9x^2+2 domain

f (x) = 9 x^{2} + 2

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f (x) = \frac{( x + 1 )}{( 2 x + 1 )}

simplify (-1.2)(-9.4)simplify

(- 1.2) (- 9.4)

Frequently Asked Questions (FAQ)

What is the midpoint (2,-6),(4,10) ?
The midpoint (2,-6),(4,10) is (3,2)