en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(x+4)^{2/7}

Solution

extreme points

f (x) = (x + 4)^{\frac{2}{7}}

Solution

Minimum (- 4, 0)

Solution steps

f^{'} (x) = \frac{2}{7 ( x + 4 ) ^{\frac{5}{7}}}

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

(x + 4)^{\frac{2}{7}} : 0

Minimum (- 4, 0)

Popular Examples

inverse of y=x^2+x inverse

y = x^{2} + x

domain of f(x)=(3/2)/(2sqrt(5/2+3/2 x))domain

f (x) = \frac{\frac{3}{2}}{2 \frac{5}{2} + \frac{3}{2} x}

range of x-5 range

x - 5

critical f(x)=-(x^2)/2-3x-1/2 critical points

f (x) = - \frac{x ^{2}}{2} - 3 x - \frac{1}{2}

asymptotes of y=(2e^x)/(e^x-5)asymptotes

y = \frac{2 e ^{x}}{e ^{x} - 5}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x+4)^{2/7} ?
The extreme f(x)=(x+4)^{2/7} is Minimum(-4,0)