What is the extreme f(x)= 5/4 x^2-12x+34 ?

The extreme f(x)= 5/4 x^2-12x+34 is Minimum(24/5 , 26/5)

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extreme f(x)= 5/4 x^2-12x+34

extreme points

f (x) = \frac{5}{4} x^{2} - 12 x + 34

Minimum (\frac{24}{5}, \frac{26}{5})

Solution steps

f^{'} (x) = \frac{5 x}{2} - 12

Find intervals:

Decreasing

: - \infty < x < \frac{24}{5},

Increasing

: \frac{24}{5} < x < \infty

Plug

x = \frac{24}{5}

into

\frac{5}{4} x^{2} - 12 x + 34 : \frac{26}{5}

Minimum (\frac{24}{5}, \frac{26}{5})

f (x) = \frac{x + 2}{x ^{2} - 2 x - 8}

f (x) = - x^{3} - 3 x^{2} - 1

y = - \frac{5}{2} x + 4

8 x + 6 y = - 4

13 = 0 \cdot 16 + b

What is the extreme f(x)= 5/4 x^2-12x+34 ?
The extreme f(x)= 5/4 x^2-12x+34 is Minimum(24/5 , 26/5)