What is the domain of f(x)=(sqrt(2x-5))/(x^2-5x+4) ?

The domain of f(x)=(sqrt(2x-5))/(x^2-5x+4) is 5/2 4

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domain of f(x)=(sqrt(2x-5))/(x^2-5x+4)

domain

f (x) = \frac{2 x - 5}{x ^{2} - 5 x + 4}

\frac{5}{2} \leq x < 4 or x > 4

Interval Notation

[\frac{5}{2}, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{5}{2}

Find undefined (singularity) points:

x = 4, x = 1

Combine real regions and undefined points for final function domain

\frac{5}{2} \leq x < 4 or x > 4

f (x) = x^{2} + 64

5 sin (4 x - π)

\frac{x ^{2} - x}{x ^{2} + 2 x}

f (x) = x^{2} + 8

\frac{x ^{2} + 1}{x}

What is the domain of f(x)=(sqrt(2x-5))/(x^2-5x+4) ?
The domain of f(x)=(sqrt(2x-5))/(x^2-5x+4) is 5/2 <= x<4\lor x>4