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Popular >

inflection y=x^3+3x^2+3x+2

Solution

inflection points

y = x^{3} + 3 x^{2} + 3 x + 2

Solution

(- 1, 1)

Solution steps

f^{''} (x) = 6 x + 6

Find intervals:

Concave Downward

: - \infty < x < - 1,

Concave Upward

: - 1 < x < \infty

Plug

x = - 1

into

x^{3} + 3 x^{2} + 3 x + 2 : 1

(- 1, 1)

Popular Examples

slope of y= 1/4 x slope

y = \frac{1}{4} x

range of f(x)=sqrt(3x-1)range

f (x) = 3 x - 1

extreme f(x)=ln(6x^2-6x-11)extreme points

f (x) = ln (6 x^{2} - 6 x - 11)

slope of y= 1/3 x-1 slope

y = \frac{1}{3} x - 1

critical x/(x^2+12x+32)critical points

\frac{x}{x ^{2} + 12 x + 32}

Frequently Asked Questions (FAQ)

What is the inflection y=x^3+3x^2+3x+2 ?
The inflection y=x^3+3x^2+3x+2 is (-1,1)