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Popular >

midpoint (4,16),(-12,-8)

Solution

midpoint

(4, 16), (- 12, - 8)

Solution

(- 4, 4)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (4, 16), (x_{2}, y_{2}) = (- 12, - 8)

= (\frac{- 12 + 4}{2}, \frac{- 8 + 16}{2})

Refine

= (- 4, 4)

Popular Examples

domain of f(x)=(2x)/(x^2-1)domain

f (x) = \frac{2 x}{x ^{2} - 1}

domain of f(x)=3+9/x domain

f (x) = 3 + \frac{9}{x}

slope of y=-2x+8 slope

y = - 2 x + 8

critical x^7+x^2-15 critical points

x^{7} + x^{2} - 15

inverse of sqrt(1-x^2)inverse

1 - x^{2}

Frequently Asked Questions (FAQ)

What is the midpoint (4,16),(-12,-8) ?
The midpoint (4,16),(-12,-8) is (-4,4)