What is the inverse of sqrt(1-x^2) ?

The inverse of sqrt(1-x^2) is sqrt(-x^2+1),-sqrt(-x^2+1)

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inverse of sqrt(1-x^2)

inverse

1 - x^{2}

- x^{2} + 1, - - x^{2} + 1

Solution steps

y = 1 - x^{2}

Replace

x

with

y

x = 1 - y^{2}

Solve for

y, x = 1 - y^{2}

- x^{2} + 1, - - x^{2} + 1

f (x) = x^{2} - 3 x + 3

f (x) = x^{3} - 8 x^{2} + 9 x + 18 = 0

f (x) = \frac{x ^{2} - 1}{x}

f (x) = \frac{x - 1}{( x + 3 ) ( x - 2 )}

f (x) = \frac{2}{x - 6}

What is the inverse of sqrt(1-x^2) ?
The inverse of sqrt(1-x^2) is sqrt(-x^2+1),-sqrt(-x^2+1)