What is the range of f(x)=sqrt(x^2-81) ?

The range of f(x)=sqrt(x^2-81) is f(x)>= 0

Popular >

range of f(x)=sqrt(x^2-81)

range

f (x) = x^{2} - 81

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x^{2} - 81 : x \leq - 9 or x \geq 9

Extreme Points of

x^{2} - 81 :

Minimum

(- 9, 0),

Minimum

(9, 0)

Find the range for the interval

- \infty < x \leq - 9 : 0 \leq f (x) < \infty

Find the range for the interval

9 \leq x < \infty : 0 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 0 or f (x) \geq 0

f (x) \geq 0

f (x) = 2 y (y - 3) (y + 1)^{2}

f (x) = \frac{1}{x ^{2} + 1}

\frac{2}{3} x + 4 - 1

f (x) = x^{2} + x - 2

f (x) = x^{3} - x^{2} + 4 x + 2

What is the range of f(x)=sqrt(x^2-81) ?
The range of f(x)=sqrt(x^2-81) is f(x)>= 0