What is the amplitude of f(t)=-1/2 sin(3t-2pi) ?

The amplitude of f(t)=-1/2 sin(3t-2pi) is 0.5

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amplitude of f(t)=-1/2 sin(3t-2pi)

amplitude

f (t) = - \frac{1}{2} sin (3 t - 2 π)

0.5

Solution steps

f (x) = - \frac{1}{2} sin (3 t - 2 π), A = - \frac{1}{2}

Therefore, the amplitude |A| is

0.5

0.5

f (x) = 2 x^{3} - 3 x^{2} + 9 x - 3

f (x) = x^{2} (x^{2} - 4)

\frac{x - 1}{x ^{2} + 1}

- \frac{4}{3}

y = - 3 x - 4

What is the amplitude of f(t)=-1/2 sin(3t-2pi) ?
The amplitude of f(t)=-1/2 sin(3t-2pi) is 0.5