What is the domain of f(x)=(2x-1)/(x^2-2x-8) ?

The domain of f(x)=(2x-1)/(x^2-2x-8) is x 4

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domain of f(x)=(2x-1)/(x^2-2x-8)

domain

f (x) = \frac{2 x - 1}{x ^{2} - 2 x - 8}

x < - 2 or - 2 < x < 4 or x > 4

Interval Notation

(- \infty, - 2) \cup (- 2, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 2

The function domain

x < - 2 or - 2 < x < 4 or x > 4

(x - 6)^{2}

f (x) = \frac{1}{( x - 1 )}

2 x^{2} - 5

f (x) = \frac{1}{3 - 25 - x ^{2}}

y = - 4 x - 3

What is the domain of f(x)=(2x-1)/(x^2-2x-8) ?
The domain of f(x)=(2x-1)/(x^2-2x-8) is x<-2\lor-2<x<4\lor x>4