What is the inverse of f(x)=2(x-3)^2 ?

The inverse of f(x)=2(x-3)^2 is sqrt(x/2)+3,-sqrt(x/2)+3

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inverse of f(x)=2(x-3)^2

inverse

f (x) = 2 (x - 3)^{2}

\frac{x}{2} + 3, - \frac{x}{2} + 3

Solution steps

y = 2 (x - 3)^{2}

Replace

x

with

y

x = 2 (y - 3)^{2}

Solve for

y, x = 2 (y - 3)^{2}

\frac{x}{2} + 3, - \frac{x}{2} + 3

f (x) = - \frac{2 x}{x - 1}

5 x - 3

f (x) = 4 - (x - 3)^{2}

\frac{x ^{2} - 16}{2 x ^{2} - 11 x + 12}

(- 1, 4), (5, - 6)

What is the inverse of f(x)=2(x-3)^2 ?
The inverse of f(x)=2(x-3)^2 is sqrt(x/2)+3,-sqrt(x/2)+3