What is the domain of f(x)=ln(9x^2+1) ?

The domain of f(x)=ln(9x^2+1) is -infinity <x<infinity

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domain of f(x)=ln(9x^2+1)

domain

f (x) = ln (9 x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = \frac{( x - 9 )}{( x - 2 )}

f (x) = \frac{x - 2}{4 x - 16}

f (x) = \frac{1}{2 - 8 - e ^{5 t}}

f (x) = \frac{1}{x + 2}

6 - x

What is the domain of f(x)=ln(9x^2+1) ?
The domain of f(x)=ln(9x^2+1) is -infinity <x<infinity