extreme y=x^5

Lösung

extrempunkte

y = x^{5}

Sattel (0, 0)

Schritte zur Lösung

f^{'} (x) = 5 x^{4}

Intervalle finden:

Ansteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = 0

x^{5} : 0

Sattel (0, 0)

e x t re m e f (x) = 5 y - 5 x + x y - 10

e x t re m e f (x) = ln (x^{2} + 7 x + 15), - 4 \leq x \leq 1

e x t re m e f (x) = - 3 x^{2} + 18 x - 3

e x t re m e f (x) = \frac{( - 2 x + 10 )}{( x - 15 ) ^{11}}

e x t re m e f (x, y) = - 4 y^{2} - 5 x^{3} + 13 x^{2}