((x-7)^2)/3+((y+11)^2)/5 =1

Lösung

\frac{( x - 7 ) ^{2}}{3} + \frac{( y + 11 ) ^{2}}{5} = 1

(h, k) = (7, - 11), a = 3, b = 5

Schritte zur Lösung

\frac{( x - 7 ) ^{2}}{3} + \frac{( y + 11 ) ^{2}}{5} = 1

Rewrite

\frac{( x - 7 ) ^{2}}{3} + \frac{( y + 11 ) ^{2}}{5} = 1

in the form of the standard ellipse equation

\frac{( x - 7 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - ( - 11 ) ) ^{2}}{( 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (7, - 11), a = 3, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (7, - 11), b = 5, a = 3

20 x^{2} + 4 y^{2} = 5

\frac{( x - 5 ) ^{2}}{12} + \frac{( y + 2 ) ^{2}}{16} = 1

x^{2} + 2 y^{2} - 10 x + 8 y + 29 = 0

16 x^{2} + 4 y^{2} - 32 x + 16 y - 32 = 0

(\frac{( x + 1 ) ^{2}}{4}) + y^{2} = 1