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Beliebt Geometry >

16x^2+4y^2-32x+16y-32=0

Lösung

16 x^{2} + 4 y^{2} - 32 x + 16 y - 32 = 0

Lösung

(h, k) = (1, - 2), a = 2, b = 4

Schritte zur Lösung

16 x^{2} + 4 y^{2} - 32 x + 16 y - 32 = 0

Rewrite

16 x^{2} + 4 y^{2} - 32 x + 16 y - 32 = 0

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 2), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, - 2), b = 4, a = 2

Graph

Beliebte Beispiele

(((x+1)^2)/4)+y^2=1

(\frac{( x + 1 ) ^{2}}{4}) + y^{2} = 1

((x-5)^2)/(49)+((y+4)^2)/(81)=1

\frac{( x - 5 ) ^{2}}{49} + \frac{( y + 4 ) ^{2}}{81} = 1

- (x - 2)^{2} - y^{2} = 4

(x^2)/(5.66^2)+(y^2)/(3.59^2)=1

\frac{x ^{2}}{5.6 6 ^{2}} + \frac{y ^{2}}{3.5 9 ^{2}} = 1

5 x^{2} + 2 y^{2} = 2