y^2+x-4y=5

Lösung

y^{2} + x - 4 y = 5

(h, k) = (9, 2), p = - \frac{1}{4}

Schritte zur Lösung

y^{2} + x - 4 y = 5

Rewrite

y^{2} + x - 4 y = 5

in the standard form

4 (- \frac{1}{4}) (x - 9) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (9, 2), p = - \frac{1}{4}

y^{2} + 6 y + 16 x - 23 = 0

x^{2} > y

x + 3 y^{2} - y = 0

x^{2} - 2 x + 36 y + 28 = 0

(y - (- 3))^{2} = 2 (x - 1)