2f(x)=3x^2-x+2

Lösung

2 f (x) = 3 x^{2} - x + 2

(h, k) = (\frac{1}{6}, \frac{23}{24}), p = \frac{1}{6}

Schritte zur Lösung

2 y = 3 x^{2} - x + 2

Rewrite

2 y = 3 x^{2} - x + 2

in the standard form

4 \cdot \frac{1}{6} (y - \frac{23}{24}) = (x - \frac{1}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{6}, \frac{23}{24}), p = \frac{1}{6}

x^{2} - 6 x + y = 0

x^{2} + (y - 5) 2 = 16

x^{2} + 3 x + 2 m (x) - 1 = 0

yy - 3 x = 13

x = z^{2}