foki (x^2)/(625)+(y^2)/(400)=1

Lösung

foki

\frac{x ^{2}}{625} + \frac{y ^{2}}{400} = 1

(15, 0), (- 15, 0)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{625} + \frac{y ^{2}}{400} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 25, b = 20

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2 5^{2} - 2 0^{2} : 15

(0 + 15, 0), (0 - 15, 0)

Fasse zusammen

(15, 0), (- 15, 0)

f oc i 4 x^{2} + 25 y^{2} + 40 x - 150 y + 225 = 0

f oc i \frac{x ^{2}}{\frac{81}{4}} + \frac{y ^{2}}{\frac{25}{16}} = 1

f oc i \frac{( y - 1 ) ^{2}}{4} + \frac{( x ^{2} )}{25} = 1

f oc i x^{2} + 4 y^{2} - 4 x - 8 y - 92 = 0

f oc i x^{2} + 9 y^{2} = 36