3y^2+48x=0

Lösung

3 y^{2} + 48 x = 0

(h, k) = (0, 0), p = - 4

Schritte zur Lösung

3 y^{2} + 48 x = 0

Rewrite

3 y^{2} + 48 x = 0

in the standard form:

4 (- 4) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 4

x^{2} = 26 y

(x - 3)^{2} = 12 (y - 4)

y^{2} \leq x

3 x^{2} - 6 x + 4 - y = 0

x = - y^{2} + 8 y - 14