y^2-4y-8x+20=0

Lösung

y^{2} - 4 y - 8 x + 20 = 0

(h, k) = (2, 2), p = 2

Schritte zur Lösung

y^{2} - 4 y - 8 x + 20 = 0

Rewrite

y^{2} - 4 y - 8 x + 20 = 0

in the standard form

4 \cdot 2 (x - 2) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 2), p = 2

y^{2} - 4 x - 6 y = - 1

x^{2} - 4 x - 4 y - 8 = 0

- x^{2} - (- y) = 4

y = x^{2} + 18 x + 42

y = \frac{1}{3} x^{2} + 2 x - 1