y^2+2y-4x=7

Lösung

y^{2} + 2 y - 4 x = 7

(h, k) = (- 2, - 1), p = 1

Schritte zur Lösung

y^{2} + 2 y - 4 x = 7

Rewrite

y^{2} + 2 y - 4 x = 7

in the standard form

4 \cdot 1 \cdot (x - (- 2)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 1), p = 1

x^{2} = - 7 y

y^{2} - 3 y + 5 x + 2 = 0

(x - 3)^{2} = - 4 (y - 5)

x^{2} = - 12 (y - 3)

x + y^{2} = 10