2x^2+y=8

Lösung

2 x^{2} + y = 8

(h, k) = (0, 8), p = - \frac{1}{8}

Schritte zur Lösung

2 x^{2} + y = 8

Rewrite

2 x^{2} + y = 8

in the standard form:

4 (- \frac{1}{8}) (y - 8) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 8), p = - \frac{1}{8}

(x + 3)^{2} = y + 4

2 x^{2} + y > 0

(x - 0) + (y - 8)^{2} = 25

y - 1 = - \frac{1}{3} x (x - 4)

(x - 4)^{2} = 12 (y + 1)