de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

leitkurve y^2=(-16)/5 x

Lösung

leitkurve

y^{2} = \frac{- 16}{5} x

Lösung

x = \frac{4}{5}

Schritte zur Lösung

Rewrite

y^{2} = \frac{- 16}{5} x

in the standard form:

4 (- \frac{4}{5}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{4}{5}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{4}{5})

Fasse zusammen

x = \frac{4}{5}

Graph

Beliebte Beispiele

leitkurve y=(2X+5)(3X-7)

d i rec t r i x y = (2 X + 5) (3 X - 7)

leitkurve (y+2)^2=-16(x+9)

d i rec t r i x (y + 2)^{2} = - 16 (x + 9)

leitkurve x^2+5x-84

d i rec t r i x x^{2} + 5 x - 84

leitkurve 2x^2-32x-y+127=0

d i rec t r i x 2 x^{2} - 32 x - y + 127 = 0

leitkurve y^2+2x+6y+17=0

d i rec t r i x y^{2} + 2 x + 6 y + 17 = 0