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2^2+2(2)

Solution

2^{2} + 2 (2)

8

Solution steps

2^{2} + 2 (2)

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 + 2 (2)

Multiply and divide (left to right)

2 (2) : 4

2 (2)

Apply rule:

(a) = a

(2) = 2

= 2 \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 4

= 4 + 4

Add and subtract (left to right)

4 + 4 : 8

4 + 4

4 + 4 = 8

= 8

= 8

(- 2)^{4} + (- 9)^{0} - (- 3)^{2}

16 \div 2 - 4^{2} - (- 3)^{2}

\frac{- 16 - ( - 8 ) ( - 20 )}{( - 11 ) ( - 8 )}

4 + 2 [5 + 3 (6 + 2)]

\frac{1}{5} + \frac{3}{8}