The solution to -(0-1)^2+2 is 1

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-(0-1)^2+2

Solution

- (0 - 1)^{2} + 2

1

Solution steps

- (0 - 1)^{2} + 2

Follow the PEMDAS order of operations

Calculate within parentheses

(0 - 1) : - 1

0 - 1

0 - 1 = - 1

= - 1

= - (- 1)^{2} + 2

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 1 + 2

Add and subtract (left to right)

- 1 + 2 : 1

- 1 + 2

- 1 + 2 = 1

= 1

= 1

(8 - 2) \div 3 + 5 + 7 (9 - 6)

3 (- 2)^{2} + 12 (- 2) + 8

2 \div 3 \times 4

21 \div (1 \frac{3}{4} \times 2 \frac{2}{9})

1 0^{5} \div 2^{4}