What is 0^6-0+2(0-1)^3 ?

The solution to 0^6-0+2(0-1)^3 is -2

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0^6-0+2(0-1)^3

0^{6} - 0 + 2 (0 - 1)^{3}

- 2

Solution steps

0^{6} - 0 + 2 (0 - 1)^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(0 - 1) : - 1

0 - 1

0 - 1 = - 1

= - 1

= 0^{6} - 0 + 2 (- 1)^{3}

Calculate exponents

0^{6} : 0

0^{6}

0^{6} = 0

= 0

= 0 - 0 + 2 (- 1)^{3}

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= 0 - 0 + 2 (- 1)

Multiply and divide (left to right)

2 (- 1) : - 2

2 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 1) = - 2 \cdot 1 = - 2

= - 2

= 0 - 0 - 2

Add and subtract (left to right)

0 - 0 - 2 : - 2

0 - 0 - 2

0 - 0 = 0

= 0 - 2

0 - 2 = - 2

= - 2

= - 2

\frac{2 ^{9} - 1}{2 ^{10}}

4 + [\frac{3}{2} + \frac{4}{8}] - 6

3 (2)^{3} - 9 (2)^{2} + 7 (2) - 3

(- 7) \times (- 6) \times (- 8) + (- 4)

2 (5)^{2} + 8 (5) + 10