The solution to 2^2-2(2)+8 is 8

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2^2-2(2)+8

Solution

2^{2} - 2 (2) + 8

8

Solution steps

2^{2} - 2 (2) + 8

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 - 2 (2) + 8

Multiply and divide (left to right)

2 (2) : 4

2 (2)

Apply rule:

(a) = a

(2) = 2

= 2 \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 4

= 4 - 4 + 8

Add and subtract (left to right)

4 - 4 + 8 : 8

4 - 4 + 8

4 - 4 = 0

= 0 + 8

0 + 8 = 8

= 8

= 8

- 2 (1)^{2} - 3 (1) - 1

6^{2} + 1^{2}

5 \cdot 3^{5}

- (7 - 5 + 4)

6 \frac{3}{4} + (4 \frac{2}{4} + 5 \frac{1}{4})