What is (-4)^2+4(-4)-5 ?

The solution to (-4)^2+4(-4)-5 is -5

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(-4)^2+4(-4)-5

(- 4)^{2} + 4 (- 4) - 5

- 5

Solution steps

(- 4)^{2} + 4 (- 4) - 5

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 + 4 (- 4) - 5

Multiply and divide (left to right)

4 (- 4) : - 16

4 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 4) = - 4 \cdot 4 = - 16

= - 16

= 16 - 16 - 5

Add and subtract (left to right)

16 - 16 - 5 : - 5

16 - 16 - 5

16 - 16 = 0

= 0 - 5

0 - 5 = - 5

= - 5

= - 5

(- 4)^{2} + 4 (- 4) + 3

300 + 41 - 63 - 56 - 31 + 89 - 114 + 1056

4 (6^{2} + 1 0^{2})

(+ 60) - (- 50 - 10) - (- 7)

214 + 11/8 + 516