What is [(-3^4+2^4)^2+1]\div (-13) ?

The solution to [(-3^4+2^4)^2+1]\div (-13) is -325 1/13

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[(-3^4+2^4)^2+1]\div (-13)

[(- 3^{4} + 2^{4})^{2} + 1] \div (- 13)

- 325 \frac{1}{13}

Solution steps

[(- 3^{4} + 2^{4})^{2} + 1] \div (- 13)

Follow the PEMDAS order of operations

Calculate within parentheses

[(- 3^{4} + 2^{4})^{2} + 1] : 4226

= 4226 \div (- 13)

Multiply and divide (left to right)

4226 \div (- 13) : \frac{4226}{( - 13 )}

= \frac{4226}{( - 13 )}

Simplify

\frac{4226}{( - 13 )} : - 325 \frac{1}{13}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{4226}{13}

Convert improper fractions to mixed numbers:

\frac{4226}{13} = 325 \frac{1}{13}

= - 325 \frac{1}{13}

\frac{8}{1} + 2 \times 1

\frac{1}{3} (5)^{2} - 4

[(8 \div 2 + 6) - 4] + [3 - 2 (5)]

\frac{2 + 0 - 7 - 7 - 5 - 7 - 5 + 1 + 2 - 5}{10}

8 + (- 25) + 16 (- 25) - 16

What is [(-3^4+2^4)^2+1]\div (-13) ?
The solution to [(-3^4+2^4)^2+1]\div (-13) is -325 1/13