What is -3(0-1)^2+5 ?

The solution to -3(0-1)^2+5 is 2

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-3(0-1)^2+5

- 3 (0 - 1)^{2} + 5

2

Solution steps

- 3 (0 - 1)^{2} + 5

Follow the PEMDAS order of operations

Calculate within parentheses

(0 - 1) : - 1

0 - 1

0 - 1 = - 1

= - 1

= - 3 (- 1)^{2} + 5

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 3 \cdot 1 + 5

Multiply and divide (left to right)

- 3 \cdot 1 : - 3

- 3 \cdot 1

- 3 \cdot 1 = - 3

= - 3

= - 3 + 5

Add and subtract (left to right)

- 3 + 5 : 2

- 3 + 5

- 3 + 5 = 2

= 2

= 2

5 (- 6 + 4)

2^{3} \div 4

(- 1)^{2} - 5 (- 1)

- 10 (+ 2) + (- 5) + (+ 4) - (- 20)

3^{2} \cdot 2^{3} - (- 7)^{2} - (- 3) (- 5)