What is 6-(5+4)*3/2 ?

The solution to 6-(5+4)*3/2 is -15/2

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6-(5+4)*3/2

6 - (5 + 4) \cdot 3/2

- \frac{15}{2}

Solution steps

6 - (5 + 4) \cdot 3/2

Follow the PEMDAS order of operations

Calculate within parentheses

(5 + 4) : 9

5 + 4

5 + 4 = 9

= 9

= 6 - 9 \cdot 3/2

Multiply and divide (left to right)

9 \cdot 3/2 : \frac{27}{2}

9 \cdot 3/2

9 \cdot 3 = 27

= 27/2

27/2 = \frac{27}{2}

= \frac{27}{2}

= 6 - \frac{27}{2}

Add and subtract (left to right)

6 - \frac{27}{2} : - \frac{15}{2}

6 - \frac{27}{2}

6 - \frac{27}{2} = - \frac{15}{2}

6 - \frac{27}{2}

Convert element to fraction:

6 = \frac{6 \cdot 2}{2}

= \frac{6 \cdot 2}{2} - \frac{27}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{6 \cdot 2 - 27}{2}

6 \cdot 2 - 27 = - 15

6 \cdot 2 - 27

Multiply the numbers:

6 \cdot 2 = 12

= 12 - 27

Subtract the numbers:

12 - 27 = - 15

= - 15

= \frac{- 15}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{15}{2}

= - \frac{15}{2}

= - \frac{15}{2}

- (1)^{2} - (- 1)^{3} + (- 1)^{5}

9 (\frac{3}{3})^{2} - 6 (\frac{3}{3})

- 2 (9) - 1

4^{2} + 2^{2} - 4 \cdot 6 \div 3 \cdot 2

- 38 + (- 40) - (- 18)