What is 4^3-(24\div 6)+8 ?

The solution to 4^3-(24\div 6)+8 is 68

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4^3-(24\div 6)+8

4^{3} - (24 \div 6) + 8

68

Solution steps

4^{3} - (24 \div 6) + 8

Follow the PEMDAS order of operations

Calculate within parentheses

(24 \div 6) : 4

= 4^{3} - 4 + 8

Calculate exponents

4^{3} : 64

= 64 - 4 + 8

Add and subtract (left to right)

64 - 4 + 8 : 68

= 68

(- 3)^{3} + 5^{2}

- 36 - (- 36 \times 1)

- 36 - (- 36 \times 0)

\frac{5 ( 10 + 7 )}{2}

- 32 + \frac{64}{3} - \frac{32}{5}