What is (-4)^2+3^2-1^3-(+2)^3 ?

The solution to (-4)^2+3^2-1^3-(+2)^3 is 16

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(-4)^2+3^2-1^3-(+2)^3

(- 4)^{2} + 3^{2} - 1^{3} - (+ 2)^{3}

16

Solution steps

(- 4)^{2} + 3^{2} - 1^{3} - (2)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 + 3^{2} - 1^{3} - (2)^{3}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 16 + 9 - 1^{3} - (2)^{3}

Calculate exponents

1^{3} : 1

1^{3}

1^{3} = 1

= 1

= 16 + 9 - 1 - (2)^{3}

Calculate exponents

(2)^{3} : 8

(2)^{3}

(2)^{3} = 8

= 8

= 16 + 9 - 1 - 8

Add and subtract (left to right)

16 + 9 - 1 - 8 : 16

16 + 9 - 1 - 8

16 + 9 = 25

= 25 - 1 - 8

25 - 1 = 24

= 24 - 8

24 - 8 = 16

= 16

= 16

17 \times 9 - (161 \div 7 - 3) \div 5 \times 4

8 - \frac{2}{5} + \frac{7}{10}

4 8^{2} + 1 4^{2}

5 - 3^{2}

1 5^{2} + 1 5^{2}