What is (2+3-1)\times (-4-2+4) ?

The solution to (2+3-1)\times (-4-2+4) is -8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2+3-1)\times (-4-2+4)

(2 + 3 - 1) \cdot (- 4 - 2 + 4)

- 8

Solution steps

(2 + 3 - 1) (- 4 - 2 + 4)

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 3 - 1) : 4

2 + 3 - 1

Add and subtract (left to right)

2 + 3 = 5

= 5 - 1

5 - 1 = 4

= 4

= 4 (- 4 - 2 + 4)

Calculate within parentheses

(- 4 - 2 + 4) : - 2

- 4 - 2 + 4

Add and subtract (left to right)

- 4 - 2 = - 6

= - 6 + 4

- 6 + 4 = - 2

= - 2

= 4 (- 2)

Multiply and divide (left to right)

4 (- 2) : - 8

4 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 2) = - 4 \cdot 2 = - 8

= - 8

= - 8

(17 - 3) \times (14 - 6) - 22

4 \times 3 - 8 + 7 \times 2 - 10 + 2 \times 6

2 (9)^{2} + 18 (9) - 14

1 0^{2} + 1 0^{1} + 1 0^{0}

12 + 6^{2} + (- 3)^{4} - 8 + 9^{2}