What is 3/5 \times (1-3/8) ?

The solution to 3/5 \times (1-3/8) is 3/8

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3/5 \times (1-3/8)

\frac{3}{5} \cdot (1 - \frac{3}{8})

\frac{3}{8}

Solution steps

\frac{3}{5} (1 - \frac{3}{8})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{3}{8}) : \frac{5}{8}

1 - \frac{3}{8}

1 - \frac{3}{8} = \frac{5}{8}

1 - \frac{3}{8}

Convert element to fraction:

1 = \frac{1 \cdot 8}{8}

= \frac{1 \cdot 8}{8} - \frac{3}{8}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 8 - 3}{8}

1 \cdot 8 - 3 = 5

1 \cdot 8 - 3

Multiply the numbers:

1 \cdot 8 = 8

= 8 - 3

Subtract the numbers:

8 - 3 = 5

= 5

= \frac{5}{8}

= \frac{5}{8}

= \frac{3}{5} \cdot \frac{5}{8}

Multiply and divide (left to right)

\frac{3}{5} \cdot \frac{5}{8} : \frac{3}{8}

\frac{3}{5} \cdot \frac{5}{8}

\frac{3}{5} \cdot \frac{5}{8} = \frac{3}{8}

= \frac{3}{8}

= \frac{3}{8}

- 5 + (- 2) \frac{2}{3}

\frac{8}{3} - 8 + 6

2^{5} \cdot 3^{3}

6^{2} - 7 (8 + 6 - 3^{2})

1 7^{2} + 1 5^{2}