What is (-2)^2+3(-2)+1 ?

The solution to (-2)^2+3(-2)+1 is -1

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(-2)^2+3(-2)+1

(- 2)^{2} + 3 (- 2) + 1

- 1

Solution steps

(- 2)^{2} + 3 (- 2) + 1

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 3 (- 2) + 1

Multiply and divide (left to right)

3 (- 2) : - 6

3 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 2) = - 3 \cdot 2 = - 6

= - 6

= 4 - 6 + 1

Add and subtract (left to right)

4 - 6 + 1 : - 1

4 - 6 + 1

4 - 6 = - 2

= - 2 + 1

- 2 + 1 = - 1

= - 1

= - 1

(- 18) + (- 8) \div (- 2) + (- 3) + (- 3) \times (- 3)

(- 3) \times (6 - 8 + 4 - 3)

(3 \times 2 + 4) - (3 \times 1 + 4)

1 0^{0} + 6^{1} + (- 3)^{2} + (- 1)^{3}

3/12 + 7/18 + 2/3 - 5/30